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To show that the function is strictly decreasing over thegiven interval we must obtain the derivative of the functionand show that this is negative for all values of x on thedomain.
i got a question, i know the odd function is f(-x) = -f(x) but when you apply the RHS of rule does it affect signs of positive constants, or just values with X in?
on the RHS when you have -f(x) you have the negative of the function. So if f(x) was say f(x) = 2x+1 then -f(x) would be -(2x+1) or in other words -2x-1
But on the LHS where you have f(-x) then if f(x)=2x+1 then f(-x)=2(-x)+1 or in other words -2x+1
In this case they are different so this function is not odd
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Comments (2)
Drew H said
at 3:43 pm on Jun 18, 2009
i got a question, i know the odd function is f(-x) = -f(x) but when you apply the RHS of rule does it affect signs of positive constants, or just values with X in?
Steph Richards said
at 11:05 pm on Jun 18, 2009
on the RHS when you have -f(x) you have the negative of the function. So if f(x) was say f(x) = 2x+1 then -f(x) would be -(2x+1) or in other words -2x-1
But on the LHS where you have f(-x) then if f(x)=2x+1 then f(-x)=2(-x)+1 or in other words -2x+1
In this case they are different so this function is not odd
You don't have permission to comment on this page.